Skill 1 of 15
In Progress

Motion equations

You drive with ‘10 metres-per-second’ (start speed, let’s symbolise it $v_0$ since it is the speed after ‘zero seconds‘) and speed up with ‘2 extra metres-per-second per second’ (acceleration $a$). After 5 seconds (final time $t$) your speed will of course be 20 metres-per-second (final speed $v$), since you start with $10\,\mathrm{m/s}$ and add $2$ more 5 times:

$$\underbrace{20\,\mathrm{m/s}}_v= \underbrace{10\,\mathrm{m/s}}_{v_0}+ \underbrace{2\,\mathrm{m/s^2}}_a\cdot \underbrace{5\,\mathrm s}_t $$

With other values this pattern would still be the same. It seems to be a general recipe that:


Subscribe to valuable engineering skills for your resume or CV

Try full access with a 7-day free trial on all subscriptions.


Already subscribing? Log in: